What is the output of the following code? [[0, 1], [2, 3]].reduce( (acc, cur) => { return acc.concat(cur); }, [1, 2]);

What is the output of the following code? [[0, 1], [2, 3]].reduce( (acc, cur) => { return acc.concat(cur); }, [1, 2]);

• A. [0, 1, 2, 3, 1, 2]
• B. [6, 1, 2]
• C. [1, 2, 0, 1, 2, 3]
• D. [1, 2, 6]

Answer: (C)

The provided code snippet uses the `reduce` method to flatten an array of arrays (`[[0, 1], [2, 3]]`) while also incorporating an initial accumulator value, which is `[1, 2]`. In detail, the `reduce` function iterates through each element of the outer array. During each iteration, it takes the current value (`cur`) and concatenates it to the accumulator (`acc`). 1. Initially, the accumulator starts as `[1, 2]`. 2. In the first iteration, `cur` is `[0, 1]`. The accumulator becomes `[1, 2].concat([0, 1])`, resulting in `[1, 2, 0, 1]`. 3. In the second iteration, `cur` is `[2, 3]`. The accumulator now is `[1, 2, 0, 1].concat([2, 3])`, yielding `[1, 2, 0, 1, 2, 3]`. This results in the final output being `[1, 2, 0, 1, 2, 3]`, which aligns with the answer provided.

The provided code snippet uses the reduce method to flatten an array of arrays ([[0, 1], [2, 3]]) while also incorporating an initial accumulator value, which is [1, 2].

In detail, the reduce function iterates through each element of the outer array. During each iteration, it takes the current value (cur) and concatenates it to the accumulator (acc).

1. Initially, the accumulator starts as [1, 2].

2. In the first iteration, cur is [0, 1]. The accumulator becomes [1, 2].concat([0, 1]), resulting in [1, 2, 0, 1].

3. In the second iteration, cur is [2, 3]. The accumulator now is [1, 2, 0, 1].concat([2, 3]), yielding [1, 2, 0, 1, 2, 3].

This results in the final output being [1, 2, 0, 1, 2, 3], which aligns with the answer provided.